If you don’t think that is possible, It is actually.
[(times)].forEach(function() {
(something aka a function)
});
If you don’t think that is possible, It is actually.
[(times)].forEach(function() {
(something aka a function)
});
i don’t know what you mean. is it a question, or is it a showcase?
there are other ways to do this (there are more than i put):
for(var i = 0; i < x; i++) {
// do something until "i < x" is not true anymore (in this case, do something x times). you can change where i starts and how much i increments.
}
for(var item of array) {
// do something [array length] times. you can refer to "item" as an item in that array.
}
I actually got it from a w3 schools example. I think its this https://www.w3schools.com/jsref/jsref_foreach.asp
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99, 100].forEach(function(v, i) {
console.log(v)
})
my preferred way of doing that is this:
for (let i = 0; i < times; i++) {
console.log(i);
}
here is another way of doing it using recursion:
function repeat(n, f) {
if (n <= 0) return;
f();
repeat(n - 1, f)
}
repeat(100, function() { "Hello, world!" })